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Tesla Software Engineer Interview Questions

Review this list of 8 Tesla Software Engineer interview questions and answers verified by hiring managers and candidates.
  • Tesla logoAsked at Tesla 
    300 answers
    Video answer for 'What's your favorite product and why?'
    +289

    "Clarify "What do you mean by favorite product? Are you thinking specifically hardware, software, or a feature within those, or something non-electronic? Dealer's Choice. "Are you asking why I love this product, or to explain why this product is a market leader independent of how i feel about it? Talk about why YOU love this product. Rephrase Question With all that in mind, i want to rephrase the question. "What is your favorite software product and what features in this product"

    Tim W. - "Clarify "What do you mean by favorite product? Are you thinking specifically hardware, software, or a feature within those, or something non-electronic? Dealer's Choice. "Are you asking why I love this product, or to explain why this product is a market leader independent of how i feel about it? Talk about why YOU love this product. Rephrase Question With all that in mind, i want to rephrase the question. "What is your favorite software product and what features in this product"See full answer

    Software Engineer
    Product Design
    +4 more
  • Tesla logoAsked at Tesla 
    23 answers
    Video answer for 'Find a triplet in an array with a given sum.'
    +17

    "from typing import List def three_sum(nums: List[int]) -> List[List[int]]: nums.sort() triplets = set() for i in range(len(nums) - 2): firstNum = nums[i] l = i + 1 r = len(nums) - 1 while l 0: r -= 1 elif potentialSum < 0: l += 1 "

    Anonymous Roadrunner - "from typing import List def three_sum(nums: List[int]) -> List[List[int]]: nums.sort() triplets = set() for i in range(len(nums) - 2): firstNum = nums[i] l = i + 1 r = len(nums) - 1 while l 0: r -= 1 elif potentialSum < 0: l += 1 "See full answer

    Software Engineer
    Data Structures & Algorithms
    +3 more
  • Tesla logoAsked at Tesla 
    14 answers
    Video answer for 'Generate Parentheses'
    +9

    " O(n) time from typing import List def generate_parentheses(n: int): res = [] def generate(buf, opened, closed): if len(buf) == 2 * n: if n != 0: res.append(buf) return if opened < n: generate( buf + "(", opened + 1, closed) if closed < opened: generate(buf + ")", opened, closed + 1) generate("", 0, 0) return res debug your code below print(generate_parentheses(1"

    Rick E. - " O(n) time from typing import List def generate_parentheses(n: int): res = [] def generate(buf, opened, closed): if len(buf) == 2 * n: if n != 0: res.append(buf) return if opened < n: generate( buf + "(", opened + 1, closed) if closed < opened: generate(buf + ")", opened, closed + 1) generate("", 0, 0) return res debug your code below print(generate_parentheses(1"See full answer

    Software Engineer
    Data Structures & Algorithms
    +3 more
  • Tesla logoAsked at Tesla 
    2 answers

    "Clarifying questions: is this a brand new product, or are we improving an existing one? (i.e. are we going to have to migrate an existing codebase or are we starting from scratch?). are we resource-strapped (e.g. # engineers, time)? are there any specific priorities for the product, or should i leave it open-ended? Assume: brand new product, well-resourced, no specific priorities. It seems that there are two sides to this question: 1) technical evaluation of different languages, and 2)"

    Laura S. - "Clarifying questions: is this a brand new product, or are we improving an existing one? (i.e. are we going to have to migrate an existing codebase or are we starting from scratch?). are we resource-strapped (e.g. # engineers, time)? are there any specific priorities for the product, or should i leave it open-ended? Assume: brand new product, well-resourced, no specific priorities. It seems that there are two sides to this question: 1) technical evaluation of different languages, and 2)"See full answer

    Software Engineer
    Technical
  • Tesla logoAsked at Tesla 
    5 answers
    +2

    "def calc(expr): ans = eval(expr) return ans your code goes debug your code below print(calc("1 + 1")) `"

    Sarvesh G. - "def calc(expr): ans = eval(expr) return ans your code goes debug your code below print(calc("1 + 1")) `"See full answer

    Software Engineer
    Data Structures & Algorithms
    +3 more
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  • Tesla logoAsked at Tesla 
    4 answers
    Video answer for 'Find the minimum window substring.'

    "What about exploiting the hash set and that is it? def smallestSubstring(s: str, t: str) -> str: if len(t) > len(s): return "" r = len(s) - 1 not_found = True while r > 0 and not_found: subs_set = set(s[0:r + 1]) for c in t: if not c in subs_set: not_found = False if not_found: r -= 1 else: r += 1 l = 0 not_found = True while l < r and not_"

    Gabriele G. - "What about exploiting the hash set and that is it? def smallestSubstring(s: str, t: str) -> str: if len(t) > len(s): return "" r = len(s) - 1 not_found = True while r > 0 and not_found: subs_set = set(s[0:r + 1]) for c in t: if not c in subs_set: not_found = False if not_found: r -= 1 else: r += 1 l = 0 not_found = True while l < r and not_"See full answer

    Software Engineer
    Data Structures & Algorithms
    +1 more
  • Tesla logoAsked at Tesla 
    Add answer
    Video answer for 'Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in clockwise spiral order.'
    Software Engineer
    Data Structures & Algorithms
    +3 more
  • Tesla logoAsked at Tesla 
    13 answers
    +10

    "from typing import List def traprainwater(height: List[int]) -> int: if not height: return 0 l, r = 0, len(height) - 1 leftMax, rightMax = height[l], height[r] res = 0 while l < r: if leftMax < rightMax: l += 1 leftMax = max(leftMax, height[l]) res += leftMax - height[l] else: r -= 1 rightMax = max(rightMax, height[r]) "

    Anonymous Roadrunner - "from typing import List def traprainwater(height: List[int]) -> int: if not height: return 0 l, r = 0, len(height) - 1 leftMax, rightMax = height[l], height[r] res = 0 while l < r: if leftMax < rightMax: l += 1 leftMax = max(leftMax, height[l]) res += leftMax - height[l] else: r -= 1 rightMax = max(rightMax, height[r]) "See full answer

    Software Engineer
    Data Structures & Algorithms
    +4 more
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