"--country names are UPPERCASE but the table in the in the question showing lowercase. That's why it took me a while to figure it out until I ran the country column
WITH RECURSIVE Hierarchy AS (
SELECT
e.Emp_ID,
CONCAT(e.FirstName, ' ', e.MiddleName, ' ', e.LastName) AS FullName,
e.Manager_ID,
0 AS Level,
CASE
WHEN e.Country = 'IRELAND' THEN s.Salary * 1.09
WHEN e.Country = 'INDIA' THEN s.Salary * 0.012
ELSE s.Salary
"
Victor N. - "--country names are UPPERCASE but the table in the in the question showing lowercase. That's why it took me a while to figure it out until I ran the country column
WITH RECURSIVE Hierarchy AS (
SELECT
e.Emp_ID,
CONCAT(e.FirstName, ' ', e.MiddleName, ' ', e.LastName) AS FullName,
e.Manager_ID,
0 AS Level,
CASE
WHEN e.Country = 'IRELAND' THEN s.Salary * 1.09
WHEN e.Country = 'INDIA' THEN s.Salary * 0.012
ELSE s.Salary
"See full answer
"class Node:
def init(self, value):
self.value = value
self.children = []
def inorder_traversal(root):
if not root:
return []
result = []
n = len(root.children)
for i in range(n):
result.extend(inorder_traversal(root.children[i]))
if i == n // 2:
result.append(root.value)
if n == 0:
result.append(root.value)
return result
Example usage:
root = Node(1)
child1 = Node(2)
chil"
Teddy Y. - "class Node:
def init(self, value):
self.value = value
self.children = []
def inorder_traversal(root):
if not root:
return []
result = []
n = len(root.children)
for i in range(n):
result.extend(inorder_traversal(root.children[i]))
if i == n // 2:
result.append(root.value)
if n == 0:
result.append(root.value)
return result
Example usage:
root = Node(1)
child1 = Node(2)
chil"See full answer
"Let me try to explain it with simple life analogy
You're cooking dinner in the kitchen. Multithreading is when you've got a bunch of friends helping out. Each friend does a different job—like one chops veggies while another stirs a sauce. Everyone focuses on their task, and together, you all make the meal faster.
In a computer, it's like different jobs happening all at once, making stuff happen quicker, just like having lots of friends helping makes dinner ready faster."
Praveen D. - "Let me try to explain it with simple life analogy
You're cooking dinner in the kitchen. Multithreading is when you've got a bunch of friends helping out. Each friend does a different job—like one chops veggies while another stirs a sauce. Everyone focuses on their task, and together, you all make the meal faster.
In a computer, it's like different jobs happening all at once, making stuff happen quicker, just like having lots of friends helping makes dinner ready faster."See full answer
Software Engineer
Coding
+1 more
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"It was like say we have a library A which has a library B as a dependency and so on, how would we determine in the dependency chain that whether there is a circular depedency?"
Chris R. - "It was like say we have a library A which has a library B as a dependency and so on, how would we determine in the dependency chain that whether there is a circular depedency?"See full answer
"Question: An array of n integers is given, and a positive integer k, where k << n. k indicates that the absolute difference between each element's current index (icurrent) and the index in the sorted array (isorted) is less than k (|icurr - isorted| < k).
Sort the given array.
The most common solution is with a Heap:
def solution(arr, k):
min_heap = []
result = []
for i in range(len(arr))
heapq.heappush(min_heap, arr[i])
"
Guilherme M. - "Question: An array of n integers is given, and a positive integer k, where k << n. k indicates that the absolute difference between each element's current index (icurrent) and the index in the sorted array (isorted) is less than k (|icurr - isorted| < k).
Sort the given array.
The most common solution is with a Heap:
def solution(arr, k):
min_heap = []
result = []
for i in range(len(arr))
heapq.heappush(min_heap, arr[i])
"See full answer
"First find the node that we need to delete.
After it's found, think about ways to keep the tree BST after deleting the node.
a. If there's no left or right subtree, we found the leaf. Delete this node without any further traversing.
b. If it's not a leaf node, what node we can use from the subtree that can replace the delete node and still maintain the BST property? We can either replace the delete node with the minimum from the right subtree (if right exists) or we can replace the delete"
An D. - "First find the node that we need to delete.
After it's found, think about ways to keep the tree BST after deleting the node.
a. If there's no left or right subtree, we found the leaf. Delete this node without any further traversing.
b. If it's not a leaf node, what node we can use from the subtree that can replace the delete node and still maintain the BST property? We can either replace the delete node with the minimum from the right subtree (if right exists) or we can replace the delete"See full answer
"The user table no longer exists as expected - I get an error that user does not contain user_id.
Note that querying the table results in only user:swuoevkivrjfta
select * FROM user
`"
Evan R. - "The user table no longer exists as expected - I get an error that user does not contain user_id.
Note that querying the table results in only user:swuoevkivrjfta
select * FROM user
`"See full answer
"If 0's aren't a concern, couldn't we just
multiply all numbers.
and then divide product by each number in the list ?
if there's more than one zero, then we just return an array of 0s
if there's one zero, then we just replace 0 with product and rest 0s.
what am i missing?"
Sachin R. - "If 0's aren't a concern, couldn't we just
multiply all numbers.
and then divide product by each number in the list ?
if there's more than one zero, then we just return an array of 0s
if there's one zero, then we just replace 0 with product and rest 0s.
what am i missing?"See full answer
"You can ask some clarifying questions like
1) Ask if the list is already sorted or not
2) is zero included in the list ?
3) Natural numbers are usually positive numbers ( clarify they are non negatives)
Solution :
1) If sorted use two pointers and sort them in O(N)
2) if not sorted , -ve / only +ve numbers in the list doesn't matter - the easiest solution is
Use a priority queue and push the number and its square in each iteration
Finally return the list returned by the priority Queue. N"
Bless M. - "You can ask some clarifying questions like
1) Ask if the list is already sorted or not
2) is zero included in the list ?
3) Natural numbers are usually positive numbers ( clarify they are non negatives)
Solution :
1) If sorted use two pointers and sort them in O(N)
2) if not sorted , -ve / only +ve numbers in the list doesn't matter - the easiest solution is
Use a priority queue and push the number and its square in each iteration
Finally return the list returned by the priority Queue. N"See full answer
"Abstract class
A class that can have Abstract methods - without implementations and Concerete Methods i.e with implementation.
Can have private, protected and public access modifiers.
Supports Single inheritance i.e a class can extend only 1 abstract class
Can have constructors
Mainly used when sharing common behaviors
Interface Class
A collection of abstract methods ( can have static and default methods also - onwards of java 8)
Public, static, final are the access"
Sue G. - "Abstract class
A class that can have Abstract methods - without implementations and Concerete Methods i.e with implementation.
Can have private, protected and public access modifiers.
Supports Single inheritance i.e a class can extend only 1 abstract class
Can have constructors
Mainly used when sharing common behaviors
Interface Class
A collection of abstract methods ( can have static and default methods also - onwards of java 8)
Public, static, final are the access"See full answer
"public static int maxProfitGreedy(int[] stockPrices) {
int maxProfit = 0;
for(int i = 1; i todayPrice) {
maxProfit += tomorrowPrice - todayPrice;
}
}
return maxProfit;
}
"
Laksitha R. - "public static int maxProfitGreedy(int[] stockPrices) {
int maxProfit = 0;
for(int i = 1; i todayPrice) {
maxProfit += tomorrowPrice - todayPrice;
}
}
return maxProfit;
}
"See full answer
"WITH RECURSIVE fibonacci_series AS (
SELECT
1 AS n,
0 AS fib1,
1 AS fib2
UNION ALL
SELECT
n + 1 AS n,
fib2 AS fib1,
fib1 + fib2 AS fib2
FROM fibonacci_series
WHERE n < 20 -- Limit the series to 20 numbers
)
SELECT
n,
fib1 AS fib
FROM fibonacci_series
ORDER BY n;
`"
Yashasvi V. - "WITH RECURSIVE fibonacci_series AS (
SELECT
1 AS n,
0 AS fib1,
1 AS fib2
UNION ALL
SELECT
n + 1 AS n,
fib2 AS fib1,
fib1 + fib2 AS fib2
FROM fibonacci_series
WHERE n < 20 -- Limit the series to 20 numbers
)
SELECT
n,
fib1 AS fib
FROM fibonacci_series
ORDER BY n;
`"See full answer