Google Software Engineer Interview Questions

Hamilton D. - "no"See full answer

Jaim - "Whenever I find resistance to my idea, my general approach is to : Validate my idea Identify if it is a political reason or is it a valid engineering tech reason Assuming it is not political but it is resource/difference of opinions that are causing resistance. Then I would try to do a quick POC and show a value proposition for the idea to get the buy-in. One similar situation happened The situation was that stakeholders were promised a feature that would decrease their number of ticket"See full answer

Anonymous Narwhal - "I'm seeking a role in which I can be continually challenged to devise innovative and streamlined solutions for complex issues, particularly with regard to the persistent soaking problem. I'm excited about the opportunity to not only excel in my own performance but also to empower and enable my colleagues to perform at their absolute best. My goal is to wield my influence and magnetic qualities to not only attract but also retain top-tier engineering talent, all in alignment with our shared objec"See full answer

Moshe S. - "Law is my passion. Traveling all over the world in 5 years"See full answer

Tiago R. - "function permute(nums) { if (nums.length <= 1) { return [nums]; } const prevPermutations = permute(nums.slice(0, nums.length-1)); const currentNum = nums[nums.length-1]; const permutations = new Set(); for (let prev of prevPermutations) { for (let i=0; i < prev.length; i++) { permutations.add([...prev.slice(0, i), currentNum, ...prev.slice(i)]); } permutations.add([...prev, currentNum]); } return [...permutations]"See full answer

Lakshman B. - "As we can pass info to only one child at a time, I told that from any given node, we have to pass the info to that child(of this node) which has the largest subtree rooted at it. To calculate the subtree sizes, I used DFS. And then to calculate the minimum time to pass info to all the nodes, I used BFS picking the largest subtree child first at every node. I couldn't write the complete code in the given time and also made a mistake in telling the overall time complexity of my approach. I think t"See full answer

Praful B. - " The productofarrays() function works by first creating an empty array to store the product of the two integers. Then, it iterates through the first array and multiplies each element by each element in the second array. The product of each element is then appended to the product array. Finally, the product array is returned def productofarrays(array1, array2): """ Calculates the product of two integers represented by two arrays. Args: array1: The first array. array2: The se"See full answer

Anonymous Dingo - "Here’s a commonly used Git branching and release strategy that we used at my previous role: Branching strategy (Git-based) a. Main Branches main: Production-ready branch. Only tested and stable code is merged here. develop: Feature branches are merged here before being merged into main. b. Supporting Branches Feature Branches (feature/) Release Branches (release/) Hotfix Branches (hotfix/) 2.Release Strategy a. Continuous Deplo"See full answer

Prashant Y. - "The height of a binary tree is the maximum number of edges from the root node to any leaf node. To calculate the height of a binary tree, we can use a recursive approach. The basic idea is to compare the heights of the left and right subtrees of the root node, and return the maximum of them plus one."See full answer