Software Engineer Interview Questions

Rishi G. - "Problem Statement: The Fibonacci sequence is defined as F(n) = F(n-1) + F(n-2) with F(0) = 1 and F(1) = 1. The solution is given in the problem statement itself. If the value of n = 0, return 1. If the value of n = 1, return 1. Otherwise, return the sum of data at (n - 1) and (n - 2). Explanation: The Fibonacci sequence is a series of numbers where each number is the sum of the two preceding ones, typically starting with 0 and 1. Java Solution: public static int fib(int n"See full answer

Debajyoti B. - "As far as i know, when we type a web address in the browser- the broswer connects to the DNS server & finds the address of the website we are looking for after finding it, the browser sends an HTTP request message to the server,with a request to send a copy of the website to the user. all of this information is sent using TCP/IP protocol across your internet"See full answer

Catherine I. - "I always ask to clarify if this is a brand new team. If so, then I focus on bringing in people with strong technical aptitudes(since I'm hiring for software engineering), but also team members that have experience mentoring and good communication is a must. I look for people who have leadership qualities. I emphasize that building a brand new team isn't something I can do on my own, so the initial hires of that team are very important to help me expand it."See full answer

Mahaboob P. - "int[] sqSorted(int[] nums) { int i = 0, j = nums.length-1; int k = nums.length-1; int[] sqs = new int[nums.length]; while(i n1) { sqs[k--] = n2; j--; } else { sqs[k--] = n1; i++; } } for(int n: sqs) System.out.println(n); return sqs; }"See full answer

Shashwat K. - "Binary Search on the array and after than compare the numbers at low and the high pointers whichever is closest is the answer. Because after the binary search low will be pointing to a number which is immediate greater than x and high will be pointing to a number which is immediate lesser than x. int low = 0; int high = n-1; while(low <= high){ int mid = (low + high) / 2; if(x == arr[mid]) return mid; //if x is already present then it will be the closest else if(x < arr[mid]) high"See full answer

Anonymous Jaguar - "Code reviews, automated linting, unit tests, integration tests, validation tests"See full answer

Abel M. - "def missingNumber(nums : List[int]): -> int counter = 0 for(i in range(len(nums)): if counter != nums[i]: return counter counter += 1 return -1"See full answer

Darpan D. - "Clarifying When we say cloud gaming, we refer to a video gaming experience using cloud computing, right? Assumption: Yes. Understanding of cloud computing first. I'll use some analogies: Imagine you are looking to do heavy computing but don't have a powerful CPU and GPU. CPU and GPU are like your big calculators. You can buy a powerful CPU and GPU, but problems: It costs a lot to buy. It costs a lot to run. You don't need it 24-7. You are not a un"See full answer

Anonymous Hyena - "A load balancer accepts requests from clients (e.g. web browsers on the Internet) and backend services (e.g. a web server). Load balancers are useful for replicating backend services onto multiple machines to meet increased demand. The design of a load balancer should address the following questions: What protocols should be supported? IP allows computers to communicate using packets, similarly to how people send letters. IP packets are addressed using an IP address and port number. "See full answer

Anonymous Wasp - "I was able to provide the optimal approach and coded it up"See full answer

B. T. - "Example: bucket A: 3 liters capacity bucket B: 5 liters capacity goal: 4 liters You are asked to print the logical sequence to get to the 4 liters of water in one bucket. Follow up: How would you solve the problem if you have more than 2 buckets of water?"See full answer

Jet 1. - "`#include using namespace std; void printNumbersTillN(int n){ if(n_==0){ return; } printNumbersTillN(n-1); // go to the end -> reach 1 cout>_n; printNumbersTillN(n); }`"See full answer

Sue G. - "In Java, GC is the process of automatically identifying and reclaming memory occupied by objects that are no longer reachable.. the process involves the 3 steps Mark phase -- identify the objects that are still in use. i.e reachable sweep Phase -- removes the unreachable objects compact phase -- rearragnes objects to prevent fragmentation 4 types of Garbage collection Serial GC -- single threaded simple and compacting -- best for small applications Parrallel GC -- throughput GC"See full answer