"Hinge is a company that fosters community which I'm passionate about. I'm also excited to work on such an impactful mission to contribute to the safety of its users."
Rosmary F. - "Hinge is a company that fosters community which I'm passionate about. I'm also excited to work on such an impactful mission to contribute to the safety of its users."See full answer
"import java.util.*;
public class NetworkTopology {
public int topologytype(int N, int M, int[] input3, int[] input4) {
if (M != N - 1 && M != N) return -1; // Fast check for invalid cases
int[] degree = new int[N + 1]; // Degree of each node (1-based indexing)
// Build the degree array
for (int i = 0; i < M; i++) {
degree[input3[i]]++;
degree[input4[i]]++;
}
// Check for Bus Topology
boolean isBus = (M"
Alessandro R. - "import java.util.*;
public class NetworkTopology {
public int topologytype(int N, int M, int[] input3, int[] input4) {
if (M != N - 1 && M != N) return -1; // Fast check for invalid cases
int[] degree = new int[N + 1]; // Degree of each node (1-based indexing)
// Build the degree array
for (int i = 0; i < M; i++) {
degree[input3[i]]++;
degree[input4[i]]++;
}
// Check for Bus Topology
boolean isBus = (M"See full answer
"from typing import List
def traprainwater(height: List[int]) -> int:
if not height:
return 0
l, r = 0, len(height) - 1
leftMax, rightMax = height[l], height[r]
res = 0
while l < r:
if leftMax < rightMax:
l += 1
leftMax = max(leftMax, height[l])
res += leftMax - height[l]
else:
r -= 1
rightMax = max(rightMax, height[r])
"
Anonymous Roadrunner - "from typing import List
def traprainwater(height: List[int]) -> int:
if not height:
return 0
l, r = 0, len(height) - 1
leftMax, rightMax = height[l], height[r]
res = 0
while l < r:
if leftMax < rightMax:
l += 1
leftMax = max(leftMax, height[l])
res += leftMax - height[l]
else:
r -= 1
rightMax = max(rightMax, height[r])
"See full answer
"Definitely nice to think of this without memorization, but there is a well known algorithm for this problem, which is the Levenshtein Distance.
Lev(a,b) = len(a) if len(b) == 0
= len(b) if len(a) == 0
= lev(a[1:], b[1:] if a[0] == b[0]
= 1 + min (lev(a, b[1:]), lev(a[1:], b), lev(a[1:], b[1:]))
https://en.wikipedia.org/wiki/Levenshtein_distance
I'm sure some optimizations could be made with heuristic."
Nicholas S. - "Definitely nice to think of this without memorization, but there is a well known algorithm for this problem, which is the Levenshtein Distance.
Lev(a,b) = len(a) if len(b) == 0
= len(b) if len(a) == 0
= lev(a[1:], b[1:] if a[0] == b[0]
= 1 + min (lev(a, b[1:]), lev(a[1:], b), lev(a[1:], b[1:]))
https://en.wikipedia.org/wiki/Levenshtein_distance
I'm sure some optimizations could be made with heuristic."See full answer
"
Broke down the problem in this:
Features scope
API design
Pseudo code for specific components
Data model/schema
Back-of-the-envelope calculations
Reference links
Link to whiteboard or diagram such as https://sketchboard.me/new
Good luck!
Considerations:
Content could be potential large
Older content should clean from the server
URL: Pastebin.com/2324234
Features Scope:
user can paste any text content .TXT, .HTML
Limit on the amount content
compress data and send over"
Ayo A. - "
Broke down the problem in this:
Features scope
API design
Pseudo code for specific components
Data model/schema
Back-of-the-envelope calculations
Reference links
Link to whiteboard or diagram such as https://sketchboard.me/new
Good luck!
Considerations:
Content could be potential large
Older content should clean from the server
URL: Pastebin.com/2324234
Features Scope:
user can paste any text content .TXT, .HTML
Limit on the amount content
compress data and send over"See full answer