Software Engineer Interview Questions

Jaya S. - "Understood the problem statement by confirming details with interviewer. Approached by listing down all the basic features being provided by the platform. Platform -> Organizations can register themselves. One org can have more than one recruiters. Recruiters create jobs on the org portal. Candidate can apply to the jobs. Recruiters can accept and reject the applications. Categorized 4 parent tables by taking hints in between. The tables were USER -> ID, Name, Phone No, mail ID, Profile Des.("See full answer

Nasit S. - "Depend on the array size and number of 0's theere."See full answer

Gaddipati V. - "NA"See full answer

Prakash K. - "3.3 years , java and Angular Full stack developer "See full answer

Jawahir Y. - "Tell me about a time you were with someone on your team who was struggling to meet objectives. How did you address the situation? What kind of feedback did you give the individual? What was the outcome?"See full answer

Divya R. - "class Trie { private TrieNode root; public Trie() { root = new TrieNode(); } public void insert(String word) { TrieNode temp=root; for(int i=0; i<word.length(); i++) { if(!temp.children.containsKey(word.charAt(i))) { temp.children.put(word.charAt(i), new TrieNode()); } temp=temp.children.get(word.charAt(i)); } temp.isEndOfWord=true; } public boolean search(String word) { TrieNode temp=root; for(int i=0; i<word.length(); i++) { if(!temp.children.containsKey(word.charAt(i))) { return false; } temp"See full answer

Prashanth A. - "We are asked to calculate Sum(over value) for time in (t - window_size, t) where key in (key criteria). To develop a function to set this up. Let w be the window size. I would have an observer of some kind note the key-value, and for the first w windows just add the value to a temporary variable in memory if the key meets the key criteria. Then it would delete the oldest value and add the new value if the new key meets the criteria. At each step after "w", we would take the sum / w and store"See full answer

Anonymous Bobcat - "Use a mapping to store number characters to possible meaning, iterate through the numeronym matching all digits with their representation"See full answer

Arun G. - "An Object Oriented programming deals with data and members. An Object Oriented Programming consumes more memory. An OOPS Consist of bottom-up approach. An OOPS is more secure Than POP. POP. An POP deals with Functions. An POP is less secure compare to OOPS. An POP contains less memory. An POP doesnt contain acess Modifiers."See full answer

Sonia M. - "virtual function is a member function declared with virtual keyword in a base class. It enables derived classes to redefine this function with their own specific implementations."See full answer

Divya R. - "static boolean sudokuSolve(char board) { return sudokuSolve(board, 0, 0); } static boolean sudokuSolve(char board, int r, int c) { if(c>=board[0].length) { r=r+1; c=0; } if(r>=board.length) return true; if(boardr=='.') { for(int num=1; num<=9; num++) { boardr=(char)('0' + num); if(isValidPosition(board, r, c)) { if(sudokuSolve(board, r, c+1)) return true; } boardr='.'; } } else { return sudokuSolve(board, r, c+1); } return false; } static boolean isValidPosition(char b"See full answer