Apple Interview Questions

Gaston B. - "Use a representative of each, e.g. sort the string and add it to the value of a hashmap> where we put all the words that belong to the same anagram together."See full answer

Aymen D. - "It would have been more interesting to focus on the system design rather than the Trie DS, Interviewee could have just mentioned the Trie and passed to things more important. Interviewee should have focused on the factors on which he wants to scale the API servers, popularity of the query parts ? region may be ? A hash of many factors ? Caches should have definitely be discussed, Cache eviction policies, Cache invalidation managements... Interviewee should have mentioned which kind of API pro"See full answer

Anonymous Possum - "#inplace reversal without inbuilt functions def reverseString(s): chars = list(s) l, r = 0, len(s)-1 while l < r: chars[l],chars[r] = chars[r],chars[l] l += 1 r -= 1 reversed = "".join(chars) return reversed "See full answer

Malay K. - "While answering such a question, it is important to focus on personal growth, learning, and how the experience improved your teamwork. You want to demonstrate self-awareness, humility, and an ability to adapt. I had this experience while working on a cross-functional project that involved collaboration between the engineering and marketing teams. In the interview, I shared a story when I misjudged someone and showed unconscious bias towards due their gender, ethnicity or age. It was embarrassin"See full answer

Soutrik M. - "Applying the STAR method to explain a time when I had to teach myself certain skills to meet project demands. Situation : I was working for a medical devices company that didn't have CI-CD setup for its embedded software Task : Build the entire CI-CD pipeline from scratch using the tools available within a month Action : I had to learn Docker and other basic DevOps technologies to build this Result : We were able to reduce build time by 70% and create a process for package manage"See full answer

Pathworks P. - "To answer this, I will focus my efforts on explaining the most common type of API used in most modern software development applications - the REST API. For the purpose of simplicity, I will also keep the topics of Authorization and Authentication out of the mix. In essence, an API is a group of logic that takes in a specific set of inputs and responds with a specific set of outputs. This is analogous to going to a drive-thru and placing an order for a meal. When you give an API a bunch of"See full answer

Sireesha R. - "Use Dutch National Flag Algorithm to solve the problem"See full answer

Tiago R. - "function isValid(s) { const stack = []; for (let i=0; i < s.length; i++) { const char = s.charAt(i); if (['(', '{', '['].includes(char)) { stack.push(char); } else { const top = stack.pop(); if ((char === ')' && top !== '(') || (char === '}' && top !== '{') || (char === ']' && top !== '[')) { return false; } } } return stack.length === 0"See full answer

Amparo L. - "The reason I want to work at Apple Company is because I have great communication skills"See full answer

Scott S. - " The Situation A few months ago, our trading platform started experiencing significant latency issues during peak trading hours. This latency was affecting our ability to process real-time market data and execute trades efficiently, potentially leading to substantial financial losses and missed opportunities. Identifying the Problem The first step was to identify the root cause of the latency. I organized a team meeting with our data engineers, DevOps, and network specialists to gather"See full answer

Gabriele G. - "DFS with check of an already seen node in the graph would work from collections import deque, defaultdict from typing import List def iscourseloopdfs(idcourse: int, graph: defaultdict[list]) -> bool: stack = deque([(id_course)]) seen_courses = set() while stack: print(stack) curr_course = stack.pop() if currcourse in seencourses: return True seencourses.add(currcourse) for dependency in graph[curr_course]: "See full answer

Avon T. - "Initialize left pointer: Set a left pointer left to 0. Iterate through the array: Iterate through the array from left to right. If the current element is not 0, swap it with the element at the left pointer and increment left. Time complexity: O(n). The loop iterates through the entire array once, making it linear time. Space complexity: O(1). The algorithm operates in-place, modifying the input array directly without using additional data structures. "See full answer

Adaneir W. - "Time taken: 25 minutes My approach: I would start by listing the use cases, what could be the length of cable needed, quantifying each and weight average those. The % make the assumption that it is what it represents the share in the total nb of iphone recharges. In fact total should be more than 100% because it not exclusive but for sake of simplicity let’s say it tops at 100%. \# In details: charging next to bed: 50%generally speaking there is a bedside table that is 80 cm high and the"See full answer

Daniel M. - "Should be able to charge the airpod case when pluged into energy. Should be able to charge when the airpod case has battery. Should be able to alert if the airpod case is out of battery. Should be able to sync with non-paired devices. Should be able to sync automatically with paired devices. Should be able to sync automatically with paired devices that are closer to the airpod. Should be able to switch the connection to a device answering a call. Should be able to pause during us"See full answer

Soumya S. - "In 2019, I was given a very important problem to solve. In a team of 3 we had to build a mobility assist device. The customer segment we would go for was something we could decide. The project was very close to me as I had lost someone I loved because of cancer and I saw how reduced mobility was a huge pain point in not being able to do physical activities. My team could only think of elderly people as the main target market. As the Head of Product what I did was: 1) I helped them dive even d"See full answer

Sachin R. - "If 0's aren't a concern, couldn't we just multiply all numbers. and then divide product by each number in the list ? if there's more than one zero, then we just return an array of 0s if there's one zero, then we just replace 0 with product and rest 0s. what am i missing?"See full answer

Sammy R. - "In python def find_duplicates(arr1: List[int], arr2: List[int]) -> List[int]: result = list(set(arr1) & set(arr2)) return result "See full answer

Laksitha R. - "public static int maxProfitGreedy(int[] stockPrices) { int maxProfit = 0; for(int i = 1; i todayPrice) { maxProfit += tomorrowPrice - todayPrice; } } return maxProfit; } "See full answer

Ben G. - "Situation - A time I had to think “outside of the box” was while I was at Google working on hotel solutions for smart displays. Smart displays are mutli-modal meaning they accommodate both touch and voice. I was given the task of leading the effort of scaling a new third party solution on top of our existing first party design system. However, the pandemic caused an unfortunate turn of events in that the needs of guests changed drastically and now needed a much more voice forward solution for"See full answer