Apple Interview Questions

VContaineers - " Compare alternate houses i.e for each house starting from the third, calculate the maximum money that can be stolen up to that house by choosing between: Skipping the current house and taking the maximum money stolen up to the previous house. Robbing the current house and adding its value to the maximum money stolen up to the house two steps back. package main import ( "fmt" ) // rob function calculates the maximum money a robber can steal func maxRob(nums []int) int { ln"See full answer

Ben G. - "Situation - A time I dealt with conflict while on a team was while I was working at Shopify on physical and digital gift card refund point of sale solutions. The situation was that we were dealing with complex technical constraints including not changing particular UI components behavior to act as they should be intended. On the refund screen, the existing design was using a toggle on the same screen to bring up a modal for gift card selection to either select digital or physical options. Thi"See full answer

Gaston B. - "Use a representative of each, e.g. sort the string and add it to the value of a hashmap> where we put all the words that belong to the same anagram together."See full answer

Anonymous Possum - "#inplace reversal without inbuilt functions def reverseString(s): chars = list(s) l, r = 0, len(s)-1 while l < r: chars[l],chars[r] = chars[r],chars[l] l += 1 r -= 1 reversed = "".join(chars) return reversed "See full answer

Frederick K. - "\# An program that prints out the peak elements in a list of integers. Pseudocode: 1. Define a function that takes a list of integers as input. 2. Initialize an empty list to store the peak elements. 3. Loop through the list of integers. 4. For each element, check if it is greater than its neighbors. 5. If it is, add it to the list of peak elements. 6. Return the list of peak elements. def findpeakelements(nums): if not nums: return [] peaks = [] n = len(nums"See full answer

Oriole O. - "Situation : During my time in my previous company, I was leading a program which involved a cross-functional team. The project was to migrate all the legacy servers to Azure and had a tight deadline of 4 months. Each team had distinct goals and responsibilites to be delivered Task : My task was to collaborate with the multi regional team and ensure a smooth delivery within the defined budget and schedule. Action : I believe communication is the key to handle a cross-functional team"See full answer

Aymen D. - "It would have been more interesting to focus on the system design rather than the Trie DS, Interviewee could have just mentioned the Trie and passed to things more important. Interviewee should have focused on the factors on which he wants to scale the API servers, popularity of the query parts ? region may be ? A hash of many factors ? Caches should have definitely be discussed, Cache eviction policies, Cache invalidation managements... Interviewee should have mentioned which kind of API pro"See full answer

Pathworks P. - "To answer this, I will focus my efforts on explaining the most common type of API used in most modern software development applications - the REST API. For the purpose of simplicity, I will also keep the topics of Authorization and Authentication out of the mix. In essence, an API is a group of logic that takes in a specific set of inputs and responds with a specific set of outputs. This is analogous to going to a drive-thru and placing an order for a meal. When you give an API a bunch of"See full answer

Tiago R. - "function isValid(s) { const stack = []; for (let i=0; i < s.length; i++) { const char = s.charAt(i); if (['(', '{', '['].includes(char)) { stack.push(char); } else { const top = stack.pop(); if ((char === ')' && top !== '(') || (char === '}' && top !== '{') || (char === ']' && top !== '[')) { return false; } } } return stack.length === 0"See full answer

Avon T. - "Initialize left pointer: Set a left pointer left to 0. Iterate through the array: Iterate through the array from left to right. If the current element is not 0, swap it with the element at the left pointer and increment left. Time complexity: O(n). The loop iterates through the entire array once, making it linear time. Space complexity: O(1). The algorithm operates in-place, modifying the input array directly without using additional data structures. "See full answer

Arshia I. - "General response: Apple’s approach to delivering seamless, personalized experiences through data, while upholding a strong ethical commitment to privacy, resonates with my own values. I want to contribute to projects that optimize user engagement and create meaningful interactions on a large scale, and I believe Apple is the ideal place to make that impact. Tailored to the team: Talk about the product, its impact internally, and the customer."See full answer

Malay K. - "While answering such a question, it is important to focus on personal growth, learning, and how the experience improved your teamwork. You want to demonstrate self-awareness, humility, and an ability to adapt. I had this experience while working on a cross-functional project that involved collaboration between the engineering and marketing teams. In the interview, I shared a story when I misjudged someone and showed unconscious bias towards due their gender, ethnicity or age. It was embarrassin"See full answer

Gabriele G. - "DFS with check of an already seen node in the graph would work from collections import deque, defaultdict from typing import List def iscourseloopdfs(idcourse: int, graph: defaultdict[list]) -> bool: stack = deque([(id_course)]) seen_courses = set() while stack: print(stack) curr_course = stack.pop() if currcourse in seencourses: return True seencourses.add(currcourse) for dependency in graph[curr_course]: "See full answer

Scott S. - " The Situation A few months ago, our trading platform started experiencing significant latency issues during peak trading hours. This latency was affecting our ability to process real-time market data and execute trades efficiently, potentially leading to substantial financial losses and missed opportunities. Identifying the Problem The first step was to identify the root cause of the latency. I organized a team meeting with our data engineers, DevOps, and network specialists to gather"See full answer

Laksitha R. - "public static int maxProfitGreedy(int[] stockPrices) { int maxProfit = 0; for(int i = 1; i todayPrice) { maxProfit += tomorrowPrice - todayPrice; } } return maxProfit; } "See full answer

Soutrik M. - "Applying the STAR method to explain a time when I had to teach myself certain skills to meet project demands. Situation : I was working for a medical devices company that didn't have CI-CD setup for its embedded software Task : Build the entire CI-CD pipeline from scratch using the tools available within a month Action : I had to learn Docker and other basic DevOps technologies to build this Result : We were able to reduce build time by 70% and create a process for package manage"See full answer

Sachin R. - "If 0's aren't a concern, couldn't we just multiply all numbers. and then divide product by each number in the list ? if there's more than one zero, then we just return an array of 0s if there's one zero, then we just replace 0 with product and rest 0s. what am i missing?"See full answer