Software Engineer Interview Questions

Anonymous Dingo - "Here’s a commonly used Git branching and release strategy that we used at my previous role: Branching strategy (Git-based) a. Main Branches main: Production-ready branch. Only tested and stable code is merged here. develop: Feature branches are merged here before being merged into main. b. Supporting Branches Feature Branches (feature/) Release Branches (release/) Hotfix Branches (hotfix/) 2.Release Strategy a. Continuous Deplo"See full answer

Praful B. - " The productofarrays() function works by first creating an empty array to store the product of the two integers. Then, it iterates through the first array and multiplies each element by each element in the second array. The product of each element is then appended to the product array. Finally, the product array is returned def productofarrays(array1, array2): """ Calculates the product of two integers represented by two arrays. Args: array1: The first array. array2: The se"See full answer

Mark S. - "int a_array[10] = {3,6,4,7,2,1,9}; int index = 0; int index2 = 0; for ( index = 0; index < sizeof(a_array); index++ ) { int tmpindex = index + 1; if ( tmpindex <= sizeof(a_array) ) { for ( index2 = tmpindex; index2 < sizeof(a_array); index2++ ) { if ( aarray[index] <= aarray[index2] ) { print( "%d is the NGE of %d" array[index2], array[index]); break; "See full answer

Amparo L. - "The reason I choose to go to college is because I want to get a Degree in the hospitality field. Additionally, I want to get a diploma after I finish taking all of my college classes At Harper."See full answer

Shubhangi S. - "sanity testing, black box testing , white box testing, smoke testing,performance testing"See full answer

Rishabh N. - "I first asked few clarifying questions like the return array may need not contain the list of building in the same order, to which the interviewer agreed. Then I came up with an approach where we iterate the array from right to left and keep a max variable which will keep the value of the current max. When we find an item which is greater than max we update the max and add this element into our solution. The interviewer agreed for the approach. I discussed few corner scenarios with the interview"See full answer

Mourya C. - "I try to solve this initially using quick select where will take a pivot element and position the remaining elements and check if the current index is answer or not and continue the same but it requires o(n*n), but interviewee is expecting the best from me, so at the end i tried solving using heaps where will check the difference between k and n-k to use min or max heap after that we will heap the array, and will keep popping the element k-1 and return the peek one which leads to answer."See full answer

Iris F. - "#include #include #include using namespace std; void printComs(int prev, int start, int end, int target) { if (start >= end) return; while (start target) { end--; } else { st"See full answer

Rasika D. - "A doubly linked list is like a train where the engine is its head, and the compartments doors are interconnected, you can travel though them. The last compartment is the tail and is not connected with anything. Following is a visual: Head C1 C2 C3....Cn Tail Pseudocode: **class Node: Data pointer next pointer prev End class DLL = NULL //pointer to list insertion: if DLL is NULL: head = new Node() DLL = head DLL.prev = NU"See full answer