"Searching for podcasts over topics is quite easy nowadays. However, usually we either don't find any podcasts interesting enough or are overwhelmed with choice. What really indicates what podcast we want to listen to at the moment is our mood, energy level etc. Additionally, we typically have some requirements, like being on the train and having one hour to spend, or only a five-minute interval while preparing breakfast. As such, I want an interface that lets me search for length. I want my"
Jonas P. - "Searching for podcasts over topics is quite easy nowadays. However, usually we either don't find any podcasts interesting enough or are overwhelmed with choice. What really indicates what podcast we want to listen to at the moment is our mood, energy level etc. Additionally, we typically have some requirements, like being on the train and having one hour to spend, or only a five-minute interval while preparing breakfast. As such, I want an interface that lets me search for length. I want my"See full answer
"Binary Search on the array and after than compare the numbers at low and the high pointers whichever is closest is the answer. Because after the binary search low will be pointing to a number which is immediate greater than x and high will be pointing to a number which is immediate lesser than x.
int low = 0;
int high = n-1;
while(low <= high){
int mid = (low + high) / 2;
if(x == arr[mid]) return mid; //if x is already present then it will be the closest
else if(x < arr[mid]) high"
Shashwat K. - "Binary Search on the array and after than compare the numbers at low and the high pointers whichever is closest is the answer. Because after the binary search low will be pointing to a number which is immediate greater than x and high will be pointing to a number which is immediate lesser than x.
int low = 0;
int high = n-1;
while(low <= high){
int mid = (low + high) / 2;
if(x == arr[mid]) return mid; //if x is already present then it will be the closest
else if(x < arr[mid]) high"See full answer
"Ask my manager how urgent is my task and why it should be done if needed. If its urgent enough and I can’t wait, communicate with team explaining what goals going to be achieved by implementing and why its important"
Anonymous Starfish - "Ask my manager how urgent is my task and why it should be done if needed. If its urgent enough and I can’t wait, communicate with team explaining what goals going to be achieved by implementing and why its important"See full answer