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Hubspot Software Engineer Interview Questions

Review this list of 5 Hubspot Software Engineer interview questions and answers verified by hiring managers and candidates.
  • Hubspot logoAsked at Hubspot 
    Software Engineer
    System Design
    +1 more
  • "I said we could always revert the production issues. Solve it at DEV environment and then publish again. Interviewer gave me an example of it like a database schema change that may not be possible to revert. I said that we always used SQL scripts to upgrade and downgrade the database schema for each production deployment. So it would not be a problem for us. I guess my answer was not accepted."

    Bulent K. - "I said we could always revert the production issues. Solve it at DEV environment and then publish again. Interviewer gave me an example of it like a database schema change that may not be possible to revert. I said that we always used SQL scripts to upgrade and downgrade the database schema for each production deployment. So it would not be a problem for us. I guess my answer was not accepted."See full answer

    Software Engineer
    Behavioral
  • Hubspot logoAsked at Hubspot 

    "Colleague moved to a different role, so I decided to fill in and did outshine in showing results within the group."

    Anjali M. - "Colleague moved to a different role, so I decided to fill in and did outshine in showing results within the group."See full answer

    Software Engineer
    Behavioral
    +2 more
  • Hubspot logoAsked at Hubspot 
    Video answer for 'Find the minimum window substring.'

    "What about exploiting the hash set and that is it? def smallestSubstring(s: str, t: str) -> str: if len(t) > len(s): return "" r = len(s) - 1 not_found = True while r > 0 and not_found: subs_set = set(s[0:r + 1]) for c in t: if not c in subs_set: not_found = False if not_found: r -= 1 else: r += 1 l = 0 not_found = True while l < r and not_"

    Gabriele G. - "What about exploiting the hash set and that is it? def smallestSubstring(s: str, t: str) -> str: if len(t) > len(s): return "" r = len(s) - 1 not_found = True while r > 0 and not_found: subs_set = set(s[0:r + 1]) for c in t: if not c in subs_set: not_found = False if not_found: r -= 1 else: r += 1 l = 0 not_found = True while l < r and not_"See full answer

    Software Engineer
    Data Structures & Algorithms
    +1 more
  • Software Engineer
    Behavioral
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