"Bitshift the number to the right and keep track of the 1's you encounter. If you bitshift it completely and only encounter one 1, it is a power of two."
Nils G. - "Bitshift the number to the right and keep track of the 1's you encounter. If you bitshift it completely and only encounter one 1, it is a power of two."See full answer
"String commonStr(String str1, String str2) {
int len1 = str1.length();
int len2 = str2.length();
if (len1 == 0 || len2 == 0) return "";
// let dpx reprsent the longest common str of 0...x
int dp = new int len1 + 1;
int maxLen = 0;
int endIndex = 0;
for (int i = 1; i <= len1; i++) {
for (int j = 1; j <= len2; j++) {
if (str1.charAt(i-1) == str2.charAt(j-1)) {
dpi = dpi-1 + 1;
"
Emma X. - "String commonStr(String str1, String str2) {
int len1 = str1.length();
int len2 = str2.length();
if (len1 == 0 || len2 == 0) return "";
// let dpx reprsent the longest common str of 0...x
int dp = new int len1 + 1;
int maxLen = 0;
int endIndex = 0;
for (int i = 1; i <= len1; i++) {
for (int j = 1; j <= len2; j++) {
if (str1.charAt(i-1) == str2.charAt(j-1)) {
dpi = dpi-1 + 1;
"See full answer