Software Engineer Interview Questions

Srikar T. - "e"See full answer

Midde V. - "Front Page Layout Design for Newspaper App Header Section Logo: Displays at the top left. App Name: Displays alongside, so very prominent. Search Bar: Centered with search to find articles within the application. Navigation Menu: The links to the respective sections, World, Politics, Sports, Entertainment, and Opinion, etc Main Content Area Top Stories Carousel: It is a rotating banner that displays the top 3-5 news stories with images along with their headlines. Each story should be cl"See full answer

Shivani N. - "did well but messed up dequeue"See full answer

Divya R. - "public Double calculateRatio(String source, String destination) { Double ratio=1.0; while(graph.containsKey(source) && !visited.contains(source)) { visited.add(source); Map valueMap=graph.get(source); if(valueMap.containsKey(destination)) { return ratio*=valueMap.get(destination); } Map.Entry firstEntry=valueMap.entrySet().iterator().next(); source=firstEntry.getKey(); ratio*=firstEntry.getValue(); System.out.println("Entered"); } return null; }"See full answer

Wagdy M. - "becuase It's big comaony to work in , and I see my long term future in Cisco. also I can learn, Iprove and develop my self"See full answer

Tiago R. - "function isPalindrome(s, start, end) { while (s[start] === s[end] && end >= start) { start++; end--; } return end <= start; } function longestPalindromicSubstring(s) { let longestPalindrome = ''; for (let i=0; i < s.length; i++) { let j = s.length-1; while (s[i] !== s[j] && i <= j) { j--; } if (s[i] === s[j]) { if (isPalindrome(s, i, j)) { const validPalindrome = s.substring(i, j+1"See full answer

Divyani .. - "Did the code in Python"See full answer

Vishal T. - "Go has simpler syntax than Java. It is light weight. It is not Object Oriented. It does not support function overloading and function overriding. But these are small technical differences. Both are similar when it comes to testing. You have to create a mock object and implement an interface. Functionally, I did not feel any major difference."See full answer

Ravi C. - "boolean isMatch(String s, String p) { int i=0; int j=0; int sID=-1; int prevM=-1; while(i<s.length()){ if(j<p.length() && (s.charAt(i)==p.charAt(j) || p.charAt(j)=='?')){ i++; j++; }else if(j<p.length() && p.charAt(j)=='*'){ sID=j; prevM=i; j++; }else if(sID!=-1){ j=sID+1; prevM++; i=prevM; }else{ return false; } } while(j<p.length() && p.charAt(j)=='*') j++; if(i!=s.length() || j!=p.leng"See full answer