Interview Questions

Roy C. - "Note: This is my answer that I generated loosely while I was practicing this question. I didnt want to go down the product design framework as this is more of an execution question, so I came up with my own zombified framework to focus more on strategy + execution. Open to feedback on my answer - understand its not the most perfect! Question: How would I launch a digital library product as a Google PM Clarifications: Standalone product? : standalone Region specific: No (up to me) Goa"See full answer

Ben G. - "Situation - A time I saw a peer struggling was while I was at Google working in Mountain View. A fellow colleague of mine was consistently not meeting standards in his performance reviews and wasn’t sure why. He was upset because Google was his dream company and he wasn’t sure how to improve based on his feedback. Task - I was tasked to design a based VUI framework for our discovery space on smart displays. This colleague was acting as the VUI lead for the project while I acted as t"See full answer

Nishant S. - "The obvious thing would be explain to them the reason for saying no. But that will not help you in building strong relationships with your stakeholder. First step would be to listen - understand the reason behind their request. Their opinion should be heard. Once you have done that, only then steer the conversation in the direction of logical reasoning for your stance. Also, you could talk to them about some of the competing priorities which would be more impactful, so that they unders"See full answer

stash - "Clarification LinkedIn Premium is a premium offering for LinkedIn members through which they get access to some additional features that are not available in the free version. Members can use these features to meet their goals When we talk about LinkedIn premium we are focused on the career product and not the sales / recruiter products? —> Yes, focused on individual members. Sales needs are solved through sales navigator and recuriter lite which are specialized premium tools *Goals"See full answer

Akash C. - " from typing import Optional class Node: def init(self, val: int, prev: Optional['Node'] = None, next: Optional['Node'] = None): self.val = val self.prev = prev self.next = next def split(head): if not head or not head.next: return head slow = head fast = head.next while fast and fast.next: slow = slow.next fast = fast.next.next mid = slow.next slow.next = None if mid: mid.prev = None "See full answer

Srinivas P. - "Assume you have a talking toy that can record voice. Machine learning is this magic that you could use to make this toy really useful for yourself. For a week - talk to this toy about your favorite color, favorite breakfast, what kind of weather you like, so on. The following week you could ask questions like today's weather is so and so - what breakfast should I have? , when should I plan a play date with my friends etc.."See full answer

Tiago R. - "function spiralCopy(inputMatrix) { if (inputMatrix.length === 1) return inputMatrix[0]; let lowerY = 0; let upperY = inputMatrix.length-1; let lowerX = 0; let upperX = inputMatrix[0].length-1; const output = []; while (true) { if (lowerX > upperX) break; for (let x = lowerX; x upperY) break; for (let y = lowerY; y <= upperY; y++) { output.push(inputMatrix[y][u"See full answer

Ds S. - "Initially I asked clarifying questions like whether the tree can be empty or not and asked the interviewer to explain what is meant by left view and the explanation for the sample inputs. Then I came up with the level order traversal approach where we visit each level in the binary tree at once using a queue and at each level print the value of the first node. Interviewer seemed satisfied with the approach and asked me to code it up. Finally gave the time and space complexity of the solution."See full answer

Tiago R. - "function findRotations(nums) { if (nums.length 0 && nums[mid] > nums[mid-1]) { left = mid; } else { right = mid; } } return rig"See full answer

Pk - "Without using the window function: SELECT w1.viewer_id FROM watch_time w1 JOIN watch_time w2 ON abs(w1.month - w2.month) = 1 AND w1.viewerid = w2.viewerid AND w1.year = w2.year GROUP BY w1.viewer_id HAVING sum(CASE WHEN w1.month > w2.month AND w1.watchhours > w2.watchhours THEN 1 ELSE 0 END) > 2 `"See full answer